Take the number 192 and multiply it by each of 1, 2, and 3:
192 × 1 = 192
192 × 2 = 384
192 × 3 = 576
By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3).
The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).
What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1,2, ... , n) where n > 1?
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here.
digit = ['1', '2', '3', '4', '5', '6', '7', '8', '9']
table = []
for m in range(1,10000):
n = 1
pd = ''
while len(pd) < 9:
num = m * n
pd = pd + str(num)
n += 1
if len(pd) == 9:
table.append(pd)
pandigitals = []
for pd in table:
if sorted([i for i in pd]) == digit:
pandigitals.append(pd)
print(max(pandigitals))