Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. Run this solution at repl.io here.
num = 7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450
n = [int(x) for x in str(num)]
maxproduct = 1
for i in range(1,1000-13):
for j in range(1,12):
product = n[i]*n[i+1]*n[i+2]*n[i+3]*n[i+4]*n[i+5] \
*n[i+6]*n[i+7]*n[i+8]*n[i+9]*n[i+10]*n[i+11]*n[i+12]
if product > maxproduct:
maxproduct = product
print(maxproduct)